How fast does an electron move?

It isn't a riddle.  It is a question that I am looking up on the web.  Here is an answer, although I don't know if it is correct or not.  This answer looks like it is about .8 of 1 percent of the speed of light.  That may not be useful to know for anything, and it may not be correct.  At the moment, it is just being used as a working number to calculate something else, as you will see.

What is the mass of an electron?  It turns out to be 1/2000th the mass of a proton.  From that, perhaps you can calculate an interesting number, which I am working out now.  Don't know if it actually means anything, as I once explained, I didn't study physics.

Now, the p B11 reaction described here is said to have a cross section ( don't know what that means) of 8.7 MeV.   Let's see.  The equation for kinetic energy is .5*m* velocity squared.

8.7 MeV= .5* mass * velocity squared

mulitply by 2:    2* 8.7 MeV = mass * velocity squared

want to know what the velocity of the particle is, but I don't know the delta of the rest mass of the particle.

If you know that, you can calculate the velocity of the particle by dividing both sides by delta mass, then taking the square root of both sides.  This would yield the velocity of the particle ( I think).

The reason I'm curious is that I wonder what the velocity of the particles coming from this reaction.  The DPF device appears to release the particles in a particle beam along the z axis.  I am wondering if this kinetic energy can be harnessed directly into thrust for a propulsion device.

Update:

Calculate delta m from the famous Einstein equation: 

kinetic E = Δmc², where Δm is the change in rest mass of particle

 then it becomes:  8.7 MeV=Δmc²   divide by c²     

giving 8.7 MeV/(88,565,760,000 km/sec), the result approximates to .01 with units????

revisting this:

8.7 MeV= .5* mass * velocity squared

then

8.7 MeV= .5* .01 * velocity squared, simplifying

8.7 MeV/.005= velocity squared

1740000000= velocity squared
=41,713 units of whatever

that would make a big difference wouldn't it????


I used kilometers above, if this is kilometer per second?!

This is probably wrong.